If y = (1+3x)^2, what is dy/dx?
A good approach to solve this is to use the chain rule of differentiation. The chain rule states: dy/dx= (dy/du)*(du/dx).
In this case let u = 1+3x, so y = u^2.
Then dy/du = 2u and du/dx = 3,
so dy/dx = (2u)*3 = (2(1+3x))*3 = 6+18x
NB
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