A,B and C all lie on the line x^2 + y^2 = 49 where A is on the y axis, B is on the X axis and C is the mid point of the straight-line connecting A and B.

As we know that A and B are on the axis so sub in X=0 and Y=0 into the equation to solve for the co-ordinates A and B.For A 02+y2=49y= square root of 49 = 7Do the same for B, which gives: A= (0,7) B= (7,0)To find the midpoint between A and B, we simply add the x coordinates and divide by 2 and do the same for the y coordinates.Xc = (0+7)/2Yc= (7+0)/2So C= (3.5,3.5)

OW

Related Maths GCSE answers

All answers ▸

factorise and hence solve x^2 + 10x +18 = -3


Write 0.2(54) as a fraction in its simplest form. (Where 0.2(54) = 0.254545454...)


y is directly proportional to (d+2)^2, when d=5, y=147. d^2 is inversely proportional to x^2, when d=2, x=3. Find an equation for y in terms of x


The mean of 4 numbers is 8 when a 5th number is added the mean becomes 10, what is the 5th number?