Solve the simultaneous equations: x^2-y=16 and 2y-4=14x

Equations: (1) x^2-y=16 and (2) 2y-4=14xRearrange (2) to give y:2y-4=14x(+4) 2y=14x+4(/2) y=7x+2call the new equation (3) y=7x+2Put (3) into (1):x^2-(7x+2)=16(expand) x^2-7x-2=16(-16) x^2-7x-18=0(Factorise) (x-9)(x+2)=0so x=9 or x=-2Substitute x values into (3):when x=9:y=7(9)+2y=63+2y=65or when x=-2y=7(-2)+2y=-14+2y=-12So, either x=9 & y=65 or x=-2 & y=-12

HC
Answered by Hollie C. Maths tutor

3983 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

A rectangle has an area of 20cm^2. Its length and width are each enlarged by scale factor 3. What is the area of the enlarged rectangle?


Find the inverse of: f(x) = (2x + 3)/(x - 4)


How do I know how many roots a quadratic equation has?


Solve the simultaneous equation: y=x^2+2x-2 y=4x+6


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning