Solve the simultaneous equations: (3x+2y=3), (x-y=-4)

3x+2y=3 x-y=-4 First, we want to cancel out either x or y so that all we have left is the one we haven't cancelled and a number. To do this we can add or subtract the two equations, possibly multiplying one of the equations first. So, as the first equation as +y and the second has -y, if we add the two equations when they have the same coefficient, the y's will cancel. Therefore we can multiply the second equation by 2 to get 2x-2y=-8 (remember to multiply both sides of the equation) Therefore we have 3x+2y=3 2x-2y=-8 Add them together to get 5x=-5 From this we can see x=-1 Sub this into the other equations to confirm y=3

RB
Answered by Rohan B. Maths tutor

3483 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Question from an Edexcel GCSE Maths Higher Paper (Nov 2018) - Solve the simultaneous equations: 5x + y = 21, x-3y = 9 (3 marks)


Solve 4x+y=7 and 3x+2y=9


Find the inverse of: f(x) = (2x + 3)/(x - 4)


How do you convert between fractions, decimals and percentages?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences