Find y if dy/dx = y² sec²(x), given that y(0) = 1
1/y² dy/dx = sec²(x)∫ 1/y² dy/dx dx = ∫ sec²(x) dx-1/y + C1 = tan(x) + C2y = -1/(tan(x) + A) where A = C2 - C1y(0) = -1/A so y(0) = 1 means A = -1. Finished!
NM
1/y² dy/dx = sec²(x)∫ 1/y² dy/dx dx = ∫ sec²(x) dx-1/y + C1 = tan(x) + C2y = -1/(tan(x) + A) where A = C2 - C1y(0) = -1/A so y(0) = 1 means A = -1. Finished!
