ABCD is a rectangle with sides of lengths x centimetres and (x − 2) centimetres.If the area of ABCD is less than 15 cm^2 , determine the range of possible values of x.
First you interpret the given information and create an equation based on the question. x(x-2)<15. Then you express that equation in standard quadratic form: x^2-2x-15<0. Then you have to not forget that x cannot be smaller than 2, because a side of a rectangle cannot be negative. Then you factorise the equation: (x-5)(x+3)<0. And finally you come to the conclusion that the state range is 2<x<5.
Related Maths A Level answers
All answers ▸Where z is a complex number, what is the cartesian form of |Z-2+3i| = 1?
A curve is defined with the following parameters; x = 3 - 4t , y = 1 + 2/t . Find dy/dx in terms of x and y.
How do I find the equation of the tangent to y = e^(x^2) at the point x = 4?
Do y=3x^2+5x+12 and y=3x-8 intercept with each other? If yes, at which point(s)?