An equilibrium between hydrogen and nitrogen to make ammonia. Explain what would happen to the amount of product if a) pressure was increased b) temperature was increased c) a catalyst was added. Energy change -92KJ/mol

This is quite a complicated sounding question but it is actually quite simple if you break it down! Start by writing a balanced equation for the reaction:

3H2 (g) + N2 (g) => 2NH3 (g)

Now you can see there is four molecules on the left and two on the right, which will help with the answer. It is a good habit to always write your state symbols, especially when this question mentions pressures.

Remember causing a change in the conditions of an equilibrium results in changes to get the equilibrium back to normal.

a) An increase in pressure will cause the amount of product to increase. The equilibrium will shift to the right where there are fewer molecules in order to counteract the change, and decrease the pressure.

b) The reaction is exothermic, which means it has a negative enthalpy change, ie it gives out heat. The amount of product will decrease. The equilibrium will move to the left in the endothermic direction in order to cool the reaction, so less ammonia is produced.

c) This is a bit of a trick question! Think about it: a catalyst basically speeds up a reaction. If the reaction is at equilibrium, the catalyst will simply speed up the reaction in both directions, and not have an affect on the amount of product formed, but just cause the product to be formed more quickly.

AC
Answered by Abigail C. Chemistry tutor

9841 Views

See similar Chemistry GCSE tutors

Related Chemistry GCSE answers

All answers ▸

What is the difference between an Atom and an Ion?


What is a covalent bond?


During fractional distillation, what are we seperating and how are we seperating them?


propene and steam react to form propan-2-ol. If the yield is 75% what mass of propene is required to produce 410g of propane-2-ol. [molar masses/gmol-1 propene=42, propan-2-ol =60]


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning