Solve the simultaneous equations: 5x+y=21, x-3y=9

Step 1. Take one equation and make either x or y the subject of the formulax=9+3y, 5x+y=21Step 2. Substitute in the equation5(9+3y)+y=21Step 3. Make y the subject of the formula45+15y+y=21 (multiplied out the brackets)16y=-24 (Subtracted 45 from both sides)y=-24/16 (Divided by 16 on both sides)y=-3/2 (Scaled the fraction down) Step 4. Find out what x is equal tox=9+3(-3/2)x=4.5 or 9/2

MJ
Answered by marcus J. Maths tutor

2653 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve this simultaneous equation: (1) 2x+3y=12 (2) x+4y=11


The first 4 terms of a different sequence are: 9, 13, 17, 21. Find an expression for the nth term of the sequence


Solve: 2((x)^2) + 7x + 3, for x


solve this equation: 4(x-5)=x+7


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences