Solve the simultaneous equations: 5x+y=21, x-3y=9

Step 1. Take one equation and make either x or y the subject of the formulax=9+3y, 5x+y=21Step 2. Substitute in the equation5(9+3y)+y=21Step 3. Make y the subject of the formula45+15y+y=21 (multiplied out the brackets)16y=-24 (Subtracted 45 from both sides)y=-24/16 (Divided by 16 on both sides)y=-3/2 (Scaled the fraction down) Step 4. Find out what x is equal tox=9+3(-3/2)x=4.5 or 9/2

MJ

Related Maths GCSE answers

All answers ▸

Simplify x^2 - 9x + 20


Harry drives from Exeter to London in 4 hours at an average speed of 70km/h. Ron drives from Exeter to London in 5 hours. (a) Assuming Ron took the same route as Harry, calculate Ron's average speed.


Sketch the curve y = x^2 - 6x + 5, identifying roots and minima/maxima.


Solve the two equations: Equation 1: 2a - 5b = 11 Equation 2: 3a + 2b = 7