There are 4 blue balls, 2 red balls, and 5 green balls in a bag. James removes one ball and does not replace it. James removes a second ball. What is the probability that both balls will be the same colour.

Total number of balls = 4 + 2 + 5 = 11 (this is our denominator for first draw)Numerator is the number of each colour. When we remove a ball the denominator and numerator for that colour decrease by 1. P(2 blue) = (4/11)(3/10) = (12/110), P(2 red) = (2/11)(1/10) = (2/110), P(2 green) = (5/11)(4/11) = (20/110)To find the total probability of picking two of the same colour we add these probabilities together then simplify.Total probability = 12/110 + 2/110 + 20/110 = 34/110 = 17/55

CW
Answered by Caleb W. Maths tutor

4366 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Find the value of 5x - 3y when x = -2 and y = -4


How do you find the area of a sector of a circle if you know the radius and the angle in the centre?


There are 6 orange sweets and n total sweets in a bag. The probability of picking two sweets one at a time randomly and both being orange is 1/3. Show that n^2 - n - 90 = 0


Electricity: 23.15 cents p/day plus 13.5 cents p/unit used Gas price: 24.5 cents p/day plus 5.5 cents p/unit used (a)(i) In 90 days, a family used 1885 units of electricity. Calculate the total cost, in dollars, of the electricity they used.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning