Prove that 2Sec(x)Cot(x) is identical to 2Cosec(x)
2 Secx = 2/CosxCotx = 1/Tan x = Cosx/SinxTherefore: 2SecCotx = 2/Cosx * Cosx/Sinx = 2/Sinx = 2Cosecx
BS
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