Write 2x^2 - 16x + 6 in the form a(x + b)^2 + c where a, b and c are constants to be determined.

2x^2 - 16x + 6= 2(x^2 - 8x) + 6= 2((x-4)^2 - 16) + 6= 2(x - 4)^2 - 26So a = 2, b = -4 and c = -26

HA
Answered by Haris A. Maths tutor

7359 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

The difference between two positive numbers is 50. The second number is 50 % smaller than the first one. What are the two numbers?


I did a question the other day which expected me to know what cos(30) is without a calculator. How do I work it out?


Expand and and simplify (x^2 + 7) (x - 1)


Solve x^2+4x-5=0 by completing the square.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning