Write 2x^2 - 16x + 6 in the form a(x + b)^2 + c where a, b and c are constants to be determined.

2x^2 - 16x + 6= 2(x^2 - 8x) + 6= 2((x-4)^2 - 16) + 6= 2(x - 4)^2 - 26So a = 2, b = -4 and c = -26

HA
Answered by Haris A. Maths tutor

8161 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Q = P / (R (4-t)), P=36, R= 3, t=-2


John invests £8000 at compound interest rate of 1.5% per year. He wants to earn more than £2000 in interest. What is the LEAST time in WHOLE years that this will take?


Simplify and solve the following equation: x^2 -8x +15=0


how would you expand quadratic factors


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning