Integrate 1/(1 - 3*x) with respect to x
First substitute: u = 1 - 3xNext calculate: du/dx = -3 .... therefore dx = (-1/3) * duNow re-arrange the expression: Integrate 1/u * ( -1/3)*duNext recall the integral of 1/x is the natural logarithm, and remember the constant! The integral is: (-1/3)*ln(u) + cNow replace u: (-1/3)*ln(1-3x) + c
NM
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