What is the signed area between the curve y = x^2 - 4 and the x-axis?

The curve y = x^2 - 4 is a parabola that crosses the x axis at x = - 2 and x = 2, so the area that we are looking for is the area within the parabola when y <= 0 and -2<= x <= 2. So we expect our area to be negative, as this part of the graph of the curve lies under the x-axis.To find the area we integrate the function x^2 - 4 between -2 and 2.The solution to the integral is [x^3/3 -4x] evaluated at 2 minus [x^3/3 -4x] evaluated at -2. That will give the result 16/3 - 16 = -32/3. So the signed area is -32/3 and this is negative as expected.

Answered by Maths tutor

8143 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

(19x - 2)/((5 - x)(1 + 6x)) can be expressed as A/(5-x) + B/(1+6x) where A and B are integers. Find A and B


How do you find a turning point of a function using differentiation?


Prove that, if 1 + 3x^2 + x^3 < (1+x)^3, then x>0


Describe the 3 types of solution to a quadratic equation


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences