Express 3x+1/(x+1)(2x+1) in partial fractions
3x+1/(x+1)(2x+1)=A/(x+1) + B/(2x+1)Multiply equation by (x+1) and (2x+1) to get:3x+1= A(2x+1) + B(x+1)Let x=-1 (x+1=0 so x=-1) sub into new equation. -2= A(-1) + B (x+1)-2=-AA=2Let x=-1/2 and sub into same equation. -1/2 = A(0) + B(1/2)-1/2=1/2BB=-1Therefore 3x+1/(x+1)(2x+1) = 2/(x+1) - 1/(2x+1)
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