If x^2 + 4x + 3xy + y^3 = 6, find the first derivative.

This is an example of implicit differentiation. We differentiate with respect to x, remembering that y is a function of x. The terms without a 'y' differentiate as normal by the power rule nxn-1. This is the terms x2, 4x and the 6 on the other side of the = sign which goes to zero as it is a constant. y differentiates to dy/dx so the product rule is used on the term 3xy and the chain rule is used on the term y3. 2x + 4 + 3x*dy/dx + 3y + 3y2dy/dx = 0 As dy/dx is a product in two of the terms, we can factorise this out. dy/dx(3x + 3y2) = -(2x +3y + 4)dy/dx = -(2x + 3y + 4)/(3x + 3y2)

TD

Related Maths A Level answers

All answers ▸

how do integrate an equation with a surd or a fraction?


Sketch the graph of y=3sin(2x +pi/2)


Find the coordinates of the turning point of y=e^(2x)*cos(x)?


Show that 2(1-cos(x)) = 3sin^2(x) can be written as 3cos^2(x)-2cos(x)-1=0.