If x^2 + 4x + 3xy + y^3 = 6, find the first derivative.

This is an example of implicit differentiation. We differentiate with respect to x, remembering that y is a function of x. The terms without a 'y' differentiate as normal by the power rule nxn-1. This is the terms x2, 4x and the 6 on the other side of the = sign which goes to zero as it is a constant. y differentiates to dy/dx so the product rule is used on the term 3xy and the chain rule is used on the term y3. 2x + 4 + 3x*dy/dx + 3y + 3y2dy/dx = 0 As dy/dx is a product in two of the terms, we can factorise this out. dy/dx(3x + 3y2) = -(2x +3y + 4)dy/dx = -(2x + 3y + 4)/(3x + 3y2)

OO
Answered by Olateju O. Maths tutor

3055 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Solve D/dx (ln ( 1/cos(x) + tan (x) )


y=4x/(x^2+5)


How do i find dy/dx in terms of t for two parametric equations that are in terms of t.


What is the exact answer to (1^3 + 2^3 + 3^3)^(0.5) ?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences