The curve C has the equation y = 1/2x^3 - 9x^3/2 + 8/x + 30, find dy/dx. Show that point P(4, -8) lies on C

y = 1/2x^3 - 9x^3/2 + 8/x + 30y = 1/2x^3 - 9x^3/2 + 8x-1 + 30dy/dx = 3/2x^2 - 27/2x^1/2 - 8x^-2 + 0dy/dx = 3/2x^2 - 27/2x^1/2 - 8/x^2substitute x=4 into equation for yy = 1/2(4)^3 - 9(4)^3 + 8/4 +30y = 32 - 72 + 2 + 30y = -8therefore P lies on C

Answered by Maths tutor

8557 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How do I find the inverse of a 2x2 matrix?


If I have a picture of a graph f(x), how can I draw what |f(x)| and 3f(x-2) look like?


Find the coordinates of the centre of the circle with equation: x^2 + y^2 − 2*x + 14*y = 0


Find the stationary points of the graph x^3 + y^3 = 3xy +35


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences