The velocity of a car at time, ts^-1, during the first 20 s of its journey, is given by v = kt + 0.03t^2, where k is a constant. When t = 20 the acceleration of the car is 1.3ms^-2, what is the value of k?
Our task is to find out the value of k, which we can determine from the equations for velocity or acceleration if we know 2 of the 3 variables in either equation. We are given the value of acceleration at t(20)=1.3ms^-1, so we should substitute these values into the equation for acceleration, which we can calculate by differentiating the velocity: a = k + 0.06t. This gives us 1.3 = k + 0.06(20) -> 1.3 = k + 1.2 -> 0.1 = k.
LM
Related Maths A Level answers
All answers ▸z = 5 - 3i Find z^2 in a form of a + bi, where a and b are real constants
A particle is in equilibrium under the action of four horizontal forces of magnitudes 5 newtons acting vertically upwards ,8 newtons acting 30 degrees from the horizontal towards the left,P newtons acting vertically downwards and Q newtons acting to right
The triangle ABC is such that AC=8cm, CB=12cm, angle ACB=x radians. The area of triangle ABC = 20cm^2. Show that x=0.430 (3sf)
Solve for 0<=θ<π, the equation sin3θ-(sqrt3)cosθ=0 (C2)