The velocity of a car at time, ts^-1, during the first 20 s of its journey, is given by v = kt + 0.03t^2, where k is a constant. When t = 20 the acceleration of the car is 1.3ms^-2, what is the value of k?

Our task is to find out the value of k, which we can determine from the equations for velocity or acceleration if we know 2 of the 3 variables in either equation. We are given the value of acceleration at t(20)=1.3ms^-1, so we should substitute these values into the equation for acceleration, which we can calculate by differentiating the velocity: a = k + 0.06t. This gives us 1.3 = k + 0.06(20) -> 1.3 = k + 1.2 -> 0.1 = k.

LM
Answered by Lascelle M. Maths tutor

7876 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How do I integrate tan^2 x?


By integrating, find the area between the curve and x axis of y = x*exp(x) between x = 0 and x = 1


g(x) = ( x / (x+3) ) + ( 3(2x+1) / (x^2 + x - 6) ). Show that this can be simplified to: g(x) = (x+1) / (x-2).


How do I differentiate an expression of the form y = (ax+b)^n?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences