Solve the simultaneous equations. 2x+5y=-4 and 7x+y=19

This can be solved using either substitution or elimination. I think this question is best approached by elimination.By elimination: Multiply the second equation by 5. The minus the first equation from the new second equation. This will give 33x=99. This can be solved as x=3. When substituting this into the first equation, we get 6+5y=-4, so 5y=-10 and y=-2.

Answered by Nisha W. Maths tutor

2104 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Rationalise the following: { 5 } / { 3 - sqrt(2) }


solve: x^2= 4(x-3)^2


solve this simulatneous equations (with clear algebraic working) : 5x-2y = 33 , 5x + 8y = 18


How do you factorise a quadratic with a co-efficient in front of the x^2 - e.g: 3x^2 + 14x + 8


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy