Show that (x + 1)(x + 2)(x + 3) can be written in the form ax^3 + bx^2 + cx + d
Start by multiplying any 2 brackets together: (x + 1)(x + 2): Split the 1st bracket: x(x+2) + 1(x+2) = x2 + 2x + x + 2 = x2 + 3x + 2 Then multiply that answer with the last bracket: (x + 3)(x2 + 3x + 2): Split the 1st bracket: x(x2 +3x + 2) +3(x2 +3x + 2)= x3 + 3x2 + 2x + 3x2+ 9x + 6 = x3 + 6x2 + 11x + 6a = 1, b = 6, c = 11, d = 6.
