How do I solve simultaneous equations using the substitution method?
2y + x = 8 (equation 1) and 1 + y = 2x (equation 2)Step 1: make y subject of equation 2: y = 2x - 1 Step 2: sub this value of y into equation 1: 2(2x - 1) + x = 8 Step 3: solve the above equation to find x: 4x -2 + x = 8 --> 5x = 10 --> x = 2 Step 4: sub this value of x into either equation 1: 1 + y = 2(2) --> y = 4 - 1 --> y = 3 Answer: x = 2 and y = 3
LH
Related Maths GCSE answers
All answers ▸Solve the inequality 5x - 7 > 2x +5
The perimeter of a right-angled triangle is 72 cm. The lengths of its sides are in the ratio 3 : 4 : 5 Work out the area of the triangle.
Make a the subject of the formula p = (3a + 5)/ (4 - a)
Vectors a and b are defined by a = 2i + 3j and b = 4i - 2j, find 3a-b in terms of i and j