Solve (2x+3)(4x-2)=0

To solve a simulatious equation, you should place the contents of each bracket equal to 0.
so (2x+3)=0 and (4x-2)=0
Lets start with the equation on the left.
2x+3=0
Minus 3 from both sides of the equation leaving you with 2x=-3 Then divide both sides by 2 leaving the equation at x= -3/2 - this is your answer

for the equation on the right (4x-2)=0
4x-2=0
add 2 to both sides (as adding is opposite to minusing) giving you 4x=2 divide both sides by 4 leaving you with the answer x=2/4
(Note: This answer can be further simplified by dividing both the top and the bottom of the fraction by the same number - in this case both the top and the bottom can be divided by 2, leaving the alternate answer as 1/2)

CP
Answered by Catherine P. Maths tutor

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