Solve (2x+3)(4x-2)=0

To solve a simulatious equation, you should place the contents of each bracket equal to 0.
so (2x+3)=0 and (4x-2)=0
Lets start with the equation on the left.
2x+3=0
Minus 3 from both sides of the equation leaving you with 2x=-3 Then divide both sides by 2 leaving the equation at x= -3/2 - this is your answer

for the equation on the right (4x-2)=0
4x-2=0
add 2 to both sides (as adding is opposite to minusing) giving you 4x=2 divide both sides by 4 leaving you with the answer x=2/4
(Note: This answer can be further simplified by dividing both the top and the bottom of the fraction by the same number - in this case both the top and the bottom can be divided by 2, leaving the alternate answer as 1/2)

CP
Answered by Catherine P. Maths tutor

4036 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How do I solve the Hannahs sweets question from the 2015 GCSE paper?


The equation of the line L1 is y = 3x – 2. The equation of the line L2 is 3y – 9x + 5 = 0. Show that these two lines are parallel.


Simultaneously solve these equations 3x+y=7 and 3x-y=5


Given that your grade for your computing is based on 5 coursework that weigh differently, and you know the results of 4: 80, 75, 50 and 90 which weighs 10%, 20%, 45% and 5%. What grade do you need in your last coursework to achieve at least a B (70%)?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences