50.0 g of propene reacts with hydrochloric acid to produce 1-chloropropane. Calculate the percentage yield if only 54.0g is made.

STEPS:Write the equation CH3CHCH2 + HCl -> CH3CH2CH2Cl + H2 (where 1-chloropropane made by electrophilic addition reaction)Identify number of moles of propene used. So number of moles is m/ Mr= 50.0g / (12X3 + 7X1)= 1.19 molesAs propene to 1-chloropropane the moles ratio is 1:1, so consequently 1.19 moles of 1-chloropropane have been madeIdentify mass of 1-cholopropane mass= n. of moles X Mr= 1.19 moles X (12X3 + 7X1 + 35.5)= 93.4gPercentage yield is actual yield over theoretical X100= (54.0g / 93.4g) X100= 57.8%