A point A lies on the line y = 2x^2 - 8x + 2. A has y-coordinate (-4). Find all possible values for the x-coordinate of A.
The point A = (x', y') lies on the line y = 2x2 - 8x +2. And we are given that y' = -4.Therefore we have that -4 = 2x2 - 8x +2, which simplifies to x2 - 4x + 3 = 0. Solutions for this quadratic equation are 1 and 3.
HK
