Solve the simulaneous Equations: 5x + y = 21, x - 3y = 9
Steps to solve a simultaneous Equation:1) Make x and y coefficients the same2) Subtract or add (of which depends on scenario) equations to eliminate x or y3) Solve remaining variable4) Plug into other equation to find x or y(1) 5x+y=21(2) x-3y=9 ---------- (Multiply (2) by 5)5x + y = 215x - 15y = 45----------- (1)-(2)0 +16y = -24, y = -1.5----------- (Plug -1.5 into y in equation (1))5x - 1.5 = 215x = 22.5x = 4.5
TT
Related Maths GCSE answers
All answers ▸Mixed rugby team of 20, 5 are female. 15 play at a time. i.) What is the percentage chance of a female playing. ii.)A minimum of three females must now be on the pitch. What is the percentage chance of 4 females playing?
How do you solve two simultaneous equations? (i.e. 5x + y =21 and x - 3y =9)
Work out 51% of 400
Solve for x: 4 x + 1 = 2 x + 12