Find the equation of the straight line that is tangent to the curve 2x^2 - 5x - 3 =0 when x = 3.

First differentiate 2x2 - 5x - 3 to get 4x -5. At x = 3, the gradient of the tangent must be 7, and we know it goes through (3, 0) Plug the values into y = mx + c to get the equation of the line, which is y = 7x -21

SL

Related Maths GCSE answers

All answers ▸

Divide £700 in the ratio 5:3:2


Expand and simplify (3x-1)(2x+1)(5-x)


Solve the equation ((2x+3)/(x-4))-((2x-8)/(2x+1))=1


P has coordinates (0, -1) and Q has coordinates (4, 1). a) Find the equation of line PQ. b) P and Q are two vertices of rectangle PQRS. Find the equation of line QR.