Find the equation of the straight line that is tangent to the curve 2x^2 - 5x - 3 =0 when x = 3.

First differentiate 2x2 - 5x - 3 to get 4x -5. At x = 3, the gradient of the tangent must be 7, and we know it goes through (3, 0) Plug the values into y = mx + c to get the equation of the line, which is y = 7x -21

SL
Answered by Sarah L. Maths tutor

2980 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Rearrange the following to make 'm' the subject. 4(m - 2) = t(5m + 3)


Factorise and solve x^2 - 8x + 15 = 0


How do you solve this problem?


By completing the square, find any turning points and intersects with the x and y axes of the following curve. f(x) = 2x^2 - 12x +7


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning