Find the equation of the straight line that is tangent to the curve 2x^2 - 5x - 3 =0 when x = 3.

First differentiate 2x2 - 5x - 3 to get 4x -5. At x = 3, the gradient of the tangent must be 7, and we know it goes through (3, 0) Plug the values into y = mx + c to get the equation of the line, which is y = 7x -21

SL
Answered by Sarah L. Maths tutor

3159 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

3 1/2 - 2 1/3


How do I factorise a quadratic equation?


The equation of the line L1 is: y = 5x-4. The equation for line L2 is 2y-10x+16 = 0. Show that these two lines are parallel.


Solve 3(2x + 5) = 4 – x


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning