Solve 6/(x-3) + x/(x+4) = 1
(6(x+4) + x(x-3) )/ ((x-3)(x+4)) = 1 obtain a common denominator and write as one fraction. (6x+24+x2-3x ) /( x2-3x+4x-12) = 1 multiply out the brackets. (x2+3x+24)/ (x2+x -12)= 1 Simplify the top and bottom. x2 +3x+24 = x2+x-12 Multiply both sides by the denominator. 3x+24 = x-12 Subtract x2 from both sides. 2x+24 = -12 Subtract x from both sides. 2x = -36 Subtract 24 from both sides. x = -18 Divide both sides by 2
JR
Related Maths GCSE answers
All answers ▸Frank, Mary and Seth shared some sweets in the ratio 4:5:7. Seth got 18 more sweets than Frank. Work out the total number of sweets they shared.
solve 125^(1/3)*2^(-3)
If the hypotenuse of a triangle is 7cm and another side is 4cm, what's the length of the other side? How can I work this out?
Triangle ABC has perimeter 20 cm. AB = 7 cm. BC = 4 cm. By calculation, deduce whether triangle ABC is a right-angled triangle.