Solve 6/(x-3) + x/(x+4) = 1

(6(x+4) + x(x-3) )/ ((x-3)(x+4)) = 1 obtain a common denominator and write as one fraction. (6x+24+x²-3x ) /( x²-3x+4x-12) = 1 multiply out the brackets. (x²+3x+24)/ (x²+x -12)= 1 Simplify the top and bottom. x² +3x+24 = x²+x-12 Multiply both sides by the denominator. 3x+24 = x-12 Subtract x² from both sides. 2x+24 = -12 Subtract x from both sides. 2x = -36 Subtract 24 from both sides. x = -18 Divide both sides by 2