The Curve C has the equation 2x^2-11+13. The point Q lies on C such that the gradient of the normal to C at Q is -1/9. Find the x-co-ordinate of Q

  • Google+ icon
  • LinkedIn icon
  • 564 views

The first ste here is the find the general equation for the gradient tangential to the curve. This is done by differentiation of the equation to give 4x-11=dy/dx. dy/dx is the gradient. Now we are given the gradient of the normal. As Mt*Mn=-1 we can find that the tangential gradient is 9. plugging this into the equation we can see that 4x-11=9. rearrage to find x so x=20/4 so x=5

Matthew H. GCSE Maths tutor, A Level Maths tutor, GCSE Chemistry tuto...

About the author

is an online GCSE Maths tutor with MyTutor studying at Liverpool University

How MyTutor Works

Still stuck? Get one-to-one help from a personally interviewed subject specialist.

95% of our customers rate us

Browse tutors

We use cookies to improve your site experience. By continuing to use this website, we'll assume that you're OK with this. Dismiss

mtw:mercury1:status:ok