The distance of a particle from its start point with respect to time is given by the equation s = 5t^2 + 2t + 4, what is the acceleration of the particle at time t?

To find the velocity from the displacement you must differentiate the function with respect to time.V = (52)t^(2-1) + (21)t^(1-1) + (40)V = 10t +2To find the acceleration you must differentiate the velocity with respect to time.A = (101)t^(1-1) + (2*0)A = 10