How can i solve the following simultaneous equations? 5x + y = 4 and 3x + 2y = 5?

The general approach to solving simultaneous equations is to replace the ‘y’s in one equation with ‘x’s, or the ‘x’s with ‘y’s.

In this case, we can first take the equation 5x + y = 4 and rearrange it to get the ‘y’ on one side.



Rearranged to:



Using this new rearranged equation we can replace the ‘y’s in the other equation.

Where we have ‘y’ in 3x + 2y = 5, we can replace it with 4 - 5x.



We can then start to simplify our new equation.



Rearranging until we reach x = 3/7. We can then replace this value of ‘x’ into either of the equations.

For example, we can replace our value of ‘x’ in 5x + y = 4.



Finally, we can expand and rearrange the equation to find ‘y’.



Therefore, the value of ‘x’ is 3/7 and the value for ‘y’ is 13/7.

TS
Answered by Tarun S. Maths tutor

11365 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the simultaneous equation by elimination: 3x + y = 11 and 5x + y = 4


two connected triangles in an overall shape ABCD, find length AD


A new car costs £12,000. It decreases in value by 5% each year for the first 5 years and then increases in value by 2% after that. How much does it cost after 7 years?


Solve the simultaneous equations 5x + y = 21, and x - 3y = 9.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning