# A titration is carried out and 0.04dm^3 of sulphuric acid neutralises 0.08dm^3 sodium hydroxide of concentration 1mol/dm^3. Calculate the concentration of the sulphuric acid.

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The first thing to do with this titration calculation is write the balanced symbol equation for the reaction. Using the knowlege that when an acid and base react a salt and water is produced we can write:

H2SO4 (aq)+ 2NaOH (aq) ---> Na2SO4 (aq)+ 2H2(l)

From the balanced symbol equation we can see that 1 mole of H2SO4 neutralises 2 moles of NaOH

The next thing to do is calculate the number of moles of sodium hydroxide that were used up in the reaction.

We use the equation: number of moles = concentration x volume

N =    1 mol/dm3   x 0.08dm3 = 0.08 moles of NaOH

The number of moles of H2SO4 used up in the reaction is therefore half of this (0.04 moles) since we established from the symbol equation that 1 mole of H2SO4 neutralises 2 moles of NaOH.

Finally we can calculate the concentration of H2SO4 by using the equation :

concentration = number of moles/ volume

c = 0.04mol/ 0.04dm3 = 1mol/dm3

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