Given that y = (1 + 3x^2)^(1/3) , use the chain rule to find dy/dx in terms of x.

Take u = 1+3x2 , this gives that y = u1/3 . By the chain rule we have that dy/dx = dy/du * du/dx. By differentiating y = u1/3 with respect to u gives dy/du = (1/3)u-2/3. By differentiating u = 1 + 3x2 with respect to x gives du/dx = 6x. Using the formula highlighted gives the answer dy/dx = 2x(1+3x2)-2/3 which we have obtained by substituting u back in.

JS

Related Maths A Level answers

All answers ▸

Point P on the curve, x = 2tan( y+ π/12), has a y-coordinate of π/4. Find an equation for the normal to the curve at P.


Find the equation of the the tangent to the curve y=x^3 - 7x + 3 at the point (1,2)


Differentiation: How to use the chain rule


What is the derivative of f(x)=sqrt(3x+2)=(3x+2)^(1/2)?