The graph of y = x^2 – 1 is translated 3 units to the left to give graph A.The equation of graphA can be written in the form y=x^2 +bx+c Work out the values of b and c.

identify what the question is asking -> both translation rules and expansion of bracketstranslation rule --> translation of 3units left on x-axis actually gives a the graph of y=(x+3)^2 -1. This is because moving left on the x-axis is actually a positive addition to x-value. expansion of brackets --> showing working out and using 'FOIL method' (first, outer, inner, last) to give the following working out: y=(x+3)(x+3)-1y=x^2+3x+3x+9-1y=X^2+6x+8how does the question want the answer given:b =6 c=8