Complete the square on this equation: 2x^2 + 20x + 15 = 0.

First you need to remove the coefficient on the x^2. We do this by factorising the 2x^2 + 20x and placing the 2 from the x^2 outside a set of brackets. This looks like:2(x2+10x) +15 = 0Then we get half of the x coefficient and place it in a secondary set of squared brackets in the form (ax2 +b)2. This looks like:(x + 5)2Next we subtract from this set of brackets the square of the half of the x coefficient. Make sure to keep this within the first set of brackets. This looks like:2((x+5)2-25)+15 = 0This means when the squared brackets are multiplied out, x2 + 10x is the only thing that will be left. Finally we expand the brackets to neaten the equation.2(x+5)2 +2*-25+15 = 02(x+5)2-35=0The equation is now in complete the square form.

RL
Answered by Robyn L. Maths tutor

3531 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Factorise this quadratic = 8x^2 + 2x -3


If a right angled triangle has its longest side 7cm and another side is 4cm then how long is the other side of the triangle? Show your working


Solve( 3x−2)/4 −(2x+5)/3= (1−x )/6


Three identical isosceles triangles are joined together to make a trapezium. Each triangle has base b cm and height h cm. Work out an expression, in terms of b and h for the area of the trapezium.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning