Solve the simultaneous equations 5x + y = 21 and x - 3y = 9

To begin with, I would begin by explaining that in a situation with simultaneous equations one of the variables must be eliminated to find the values for y and x.In this specific case I would make the x variables have the same coefficient and multiply the second equation by 5 giving 5x-13y=45The next step would be to subtract one equation from the other as so: 5x-13y=45 - 5x + y = 21 resulting in an answer of -16y=24This equation can rearrange to y= -1.5Using this value in either of the original equations you can solve for xBy using x-3y=9 and rearranging for x to give x=9+3y then substituting in the value for y to obtain x=4.5

LO
Answered by Lily O. Maths tutor

3095 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Matt had 3 piles of coins, A, B and C. Altogether there was 72p. Pile B had twice as much as pile A. Pile C had three times as much as pile B.


What is completing the square and how do you do it?


Simplify fully (x^2 + 3x)/(4x + 12) ​


Write x^2+4x-12 in the form (x+a)^2+b where 'a' and 'b' are constants to be determined.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning