How do you differentiate y=x^x?

To solve this problem, you need to put it into simplest form which is putting it into natural logarithm both the RHS and LHS. Then differentiate both side with respect to x as shown below.

In(y) = ln(x^x)    - natural logarithm both side

ln(y) = xln(x)      - using the power rule

(1/y)dy/dx = x*1/x + ln(x)      - Diffrentiate both side (chain rule in the RHS) 

dy/dx = y(1+ln(x))     - multiplying  'y' in both sides

         = x^x(1+ln(x))    - replacing the value of 'y'

MT
Answered by Merhawi T. Maths tutor

5462 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

The line AB has equation 3x + 5y = 7, find; a) the gradient of AB b) the x-axis and y-axis intercepts c) sketch the graph


What are the limits of an inverse tan graph.


What is the derivative of f(x)=sqrt(3x+2)=(3x+2)^(1/2)?


Given y = 3x^(1/2) - 6x + 4, x > 0. 1) Find the integral of y with respect to x, simplifying each term. 2) Differentiate the equation for y with respect to x.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences