Solve algebraically the simultaneous equations 2x^2-y^2=17 and x+2y=1

To solve these equations, we have to rearrange the second equation to make x ‘the subject’ and then we can substitute it into the first one. First, subtract 2y from both sides so x=1-2yNext substitute this into the first equation, so 2(1-2y)2-y2=17Now expand the brackets. 2-8y+8y2-y2=17rearrange to form a quadratic equation: 7y2-8y-15=0now, factorise this: (7y-15)(y+1)=0this can be solved by considering y+1=0 and 7y-15=0, giving the solutions y=-1 and y=15/7when y=-1, x=1+2=3when y=15/7, x=1-30/7=-23/7

BH
Answered by Benjamin H. Maths tutor

13586 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

What is the pythagoras theorem?


I don't understand, what do you use sin, cos and tan for?


A game consists of 5 cups turned upside down, under one of the cups is a prize. 5 friend's pick a cup in turn and lifts it up, if they get the prize, they win , but if not, the cup is removed and the next friend picks. What position is it best to pick?


For the equation x^2 - 2x - 8 = y find: (a) The roots. (b) The y-intercept. (c) The coordinate of the turning point


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences