A scalene triangle ABC has side lengths AB=6cm, BC=4cm, and AC=x cm. The angle A, opposite BC, is 40 degrees and the angle B, opposite AC, is 50 degrees. State the sine rule and use it to find the value of x to 3 s.f.

The sine rule states that for any scalene triangle ABC the following equation holds: BC/sin(A) = AC/sin(B) = AB/sin(C).[Draw a diagram.] By drawing the triangle and substituting the values that we know into the equation, we get the following: 4/sin(40) = x/sin(50) = 6/sin(C)Angle C does not help us find x so we focus on the left-hand equation: 4/sin(40) = x/sin(50) Then multiply through by sin(50) to make x the subject and get: x = 4*sin(50)/sin(40) Use your calculator to obtain the value of x: x = 4.76701437 The question has asked us for an answer to 3 significant figures though, so we round to x = 4.77.

TC
Answered by Thomas C. Maths tutor

3817 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

f(x) = 3x - 2a || g(x) = 2ax + 1 || fg(x) = 2x + b/2


Solve this simultaneous equation: 2 + 5y = 3x, x + y = 6


What rules should I look out for when manipulating expressions?


A right-angled triangle has side lengths of 8.65cm and 10.15cm. What is the length of its hypotenuse?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning