A scalene triangle ABC has side lengths AB=6cm, BC=4cm, and AC=x cm. The angle A, opposite BC, is 40 degrees and the angle B, opposite AC, is 50 degrees. State the sine rule and use it to find the value of x to 3 s.f.

The sine rule states that for any scalene triangle ABC the following equation holds: BC/sin(A) = AC/sin(B) = AB/sin(C).[Draw a diagram.] By drawing the triangle and substituting the values that we know into the equation, we get the following: 4/sin(40) = x/sin(50) = 6/sin(C)Angle C does not help us find x so we focus on the left-hand equation: 4/sin(40) = x/sin(50) Then multiply through by sin(50) to make x the subject and get: x = 4*sin(50)/sin(40) Use your calculator to obtain the value of x: x = 4.76701437 The question has asked us for an answer to 3 significant figures though, so we round to x = 4.77.

TC
Answered by Thomas C. Maths tutor

4500 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

X=4a+3b, If a is a two digit cube number and b is a two digit square number then what is the lowest possible value for X?


If 4x + 3y = 4 and x + 2y = 2 what are the values of x and y ?


simplify 7(3y-5) - 2(10 + 4y)


Solve the following pair of simultaneous equations: 5x+2y=8 and 2x+y=7


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning