Find the tangent to the equation y=x^2 -2x +4 when x=2
When X=2 Y=2^2-2(2)+4=4 So the coordinates are (2,4)Differentiate Y so dy/dx = 2x-2Tangent Gradient when x=2 is 2(2)-2=2 so m=2We need to find the y intercept to get out tangent equationso y=2x+c , we sub in our coordinates to get 4=2(2)+c , c=0So therefore the tangent equation is y=2x
NN
Answered by Nabeel N. • Further Mathematics tutor
2601 Views
See similar Further Mathematics GCSE tutorsRelated Further Mathematics GCSE answers
All answers ▸(x+4)((x^2) - kx - 5) is expanded and simplified. The coefficient of the x^2 term twice the coefficient of the x term. Work out the value of k.
The equation 3x^2 – 5x + 4 = 0 has roots P and Q, find a quadratic equation with the roots (P + 1/2Q) and (Q + 1/2P)
How many different ways are there to seat 6 people at a round table?
Work out 7/(2x^2) + 4/3x as a single fraction in its simplest form.