Find the tangent to the equation y=x^2 -2x +4 when x=2

When X=2 Y=2^2-2(2)+4=4 So the coordinates are (2,4)Differentiate Y so dy/dx = 2x-2Tangent Gradient when x=2 is 2(2)-2=2 so m=2We need to find the y intercept to get out tangent equationso y=2x+c , we sub in our coordinates to get 4=2(2)+c , c=0So therefore the tangent equation is y=2x

NN

Related Further Mathematics GCSE answers

All answers ▸

Find the solution of 3^{4x} = 9^{(x-1)/2}.


Let Curve C be f(x)=(1/3)(x^2)+8 and line L be y=3x+k where k is a positive constant. Given that L is tangent to C, find the value of k. (6 marks approx)


Find the stationary points of y=x^3 + 3x^2 - 9x - 4


f(x) = 2x^3+6x^2-18x+1. For which values of x is f(x) an increasing function?