Find the tangent to the equation y=x^2 -2x +4 when x=2

When X=2 Y=2^2-2(2)+4=4 So the coordinates are (2,4)Differentiate Y so dy/dx = 2x-2Tangent Gradient when x=2 is 2(2)-2=2 so m=2We need to find the y intercept to get out tangent equationso y=2x+c , we sub in our coordinates to get 4=2(2)+c , c=0So therefore the tangent equation is y=2x

NN
Answered by Nabeel N. Further Mathematics tutor

2044 Views

See similar Further Mathematics GCSE tutors

Related Further Mathematics GCSE answers

All answers ▸

The curve C is given by the equation x^4 + x^2y + y^2 = 13. Find the value of dy/dx at the point (-1,3). (A-level)


write showing all working the following algebraic expression as a single fraction in its simplest form: 4-[(x+3)/ ((x^2 +5x +6)/(x-2))]


Find the solution of 3^{4x} = 9^{(x-1)/2}.


How can you divide an algebraic expression by another algebraic expression?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning