Find dy/dx when y = 5x^6 + 4x*sin(x^2)

Looking at the first element of the equation 5x6, we can simply multiply 6 by 5 to give 30 and subtract 1 from the power of x. So d/dx[5x6] = 30x5. The next element of the equation is 4xsin(x2), where we will need to use the product rule (since we have the variable x in both 4x and sin(x2) which are being multiplied) and chain rule (for sin(x2) since this is the composition of the two functions sin() and x2). From the product rule we obtain 4sin(x2) + 4xd/dx[sin(x2)]. Using the chain rule to differentiate sin(x2), we get cos(x2)d/dx[x2] = 2xcos(x2). Therefore our end result for dy/dx = 30x5 + 4sin(x2) + 4x2xcos(x2) = 30x5 + 4*sin(x2) + 8x2*cos(x2)

MJ
Answered by Mark J. Maths tutor

2695 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

What is De Moivre's theorem?


Find partial fractions of : (x+7) / ((x-3)(x+1)^2)


Question 3 on the OCR MEI C1 June 2015 paper. Evaluate the following. (i) 200^0 (ii) (9/25)^(-1/2)


Curve D has equation 3x^2+2xy-2y^2+4=0 Find the equation of the tangent at point (2,4) and give your answer in the form ax+by+c=0, were a,b and c are integers.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences