How do you multiply two brackets with two terms in them? For example (2x-3)(x+4)

We use the FOIL method to do this, where FOIL stands for First, Outside, Inside, Last. So in this example we multiply the first term of the first bracket with the first term of the second bracket (2x-3)(x+4)=2x2 Then we multiply the terms on the outer edge of the brackets, in this example; 2x and +4. (2x-3)(x+4)=2x2+8x Then we multiply the terms on the inner edge of the brackets, in this example; -3 and x. (2x-3)(x+4)=2x^2+8x-3x Finally, we multiply the last term in the first bracket with the last term in the second bracket, in this example; -3 and +4. (2x-3)(x+4)=2x^2+8x-3x-12 This is our final answer! Now we simplify by collecting like terms: 2x^2+5x-12 Note: Always be aware of the sign before the number, noting whether it is a positive or a negative integer.

OA
Answered by Oluwatose A. Maths tutor

4021 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Factorise (x+3)(x-8)


Solve the inequality 6y + 5 > 8


Given a right-angled triangle with an angle of 35 degrees and an Opposite side of 12cm, calculate the length of the hypotenuse to 3 significant figures.


Consider f:R -> R, f = x/ sqrt(x^2+1). Prove that for any a between -1 and 1, f(x)=a has only one solution.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning