Assuming no friction, describe the motion of a simple pendulum released from rest at t=0 at amplitude A? Provide information about its speed and position at characteristic times during one period. [The 1D equation of motion is described by a cosine]

The displacement of the bob of mass m is given by the equation x(t)=A cos(w*t), with no phase offset as given by the boundary conditions (zero speed at t=0). By differentiating this equation twice the first and second derivatives of displacement, i.e. speed and acceleration as a function of displacement can be obtained. By finding maxima of these quantities by looking at peaks of higher order derivatives, one can find the times t at which speed and acceleration are maximised and plot the graphs for one period.
Either we can treat this mathematically or provide physical insight into what should happen to the pendulum. As the pendulum is released from rest, the initial speed is zero. Due to the tangential component of the gravitational force, the bob of mass m is accelerated until it reaches a maximum speed at zero height. As the mass continues to move due to inertia and the gravitational force acting now opposite to its motion, it will slow down again and reach the same height as initially (assuming no air resistance etc.).

SA
Answered by Stefan A. Physics tutor

2100 Views

See similar Physics GCSE tutors

Related Physics GCSE answers

All answers ▸

What's the difference between velocity and speed?


Explain how a convection current forms when a pan of water is being heated over a stove


If Jessica weighs 45kg and sits on a seesaw at a distance of 2m from the centre of the seesaw.Micheal weighs 90kg. At what point on the opposite side should Micheal sit in order to balance the seesaw.


Hanging on a branch of a tree, a monkey sees a hunter aiming a gun at him. The monkey lets go of the branch at the exact same time the bullet is fired. Explain why the bullet hits the monkey.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning