A is the point with coordinates (5, 9) B is the point with coordinates (d, 15) The gradient of the line AB is 3 Work out the value of d.

To work out the coordinates of point B, you need to look at all of the information that is given in the question.The question tells you that the gradient of the line is 3, which implies that we need to use the general equation of a straight line: y = mx + c, where y is the y coordinate, m is the gradient, x is the x coordinate and c is the y intercept. The first step of answering the question is substituting the coordinates of point A and the gradient into the equation of a straight line. This will give you 9 = 3(5) + c. This can be rearranged to find c:9 = 3(5) + c9 = 15 + c-6 = cThe second step is therefore substituting the coordinates of point B, the gradient and the y intercept into y = mx + c. This will give you 15 = 3d – 6. This can be rearranged to find c:15 = 3d – 6 21 = 3d7 = dThe final answer is therefore d = 7.

SC
Answered by Sophie C. Maths tutor

7679 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the simultaneous equations x^2 + y^2 =13 and x= y - 5.


Write 36 as a product of prime factors. Give your answer in index form.


Solve 3y^2 – 60y + 220 = 0 using the quadratic formula:


work out: ( 4 × 10^3 )^2 + 3.5 × 10^7 and give your answer in standard form.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences