A particle, P, moves along the x-axis. At time t seconds, t > 0, the displacement, is given by x=1/2t^2(t ^2−2t+1).

Find the times when is instantaneously at rest.In order to solve this question we first have to multiply out in order to obtain the full expression of x which will be x = 1/2t^4 -2t^3+1/2t^2. Now we differentiate with respect to time we obtain v=2t^3 -3t^2+t. If P is suppose to be at rest then v will be equal zero. So we obtain an equation 0=2t^3-3t^2+t and solving the equation t(2t-1)(t-1)=0 and we obtain three different answers t=0, t=1/2 and t=1 and all answers are possible.

AK
Answered by Aleksander K. Maths tutor

18144 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find the stationary points of the curve f(x) =x^3 - 6x^2 + 9x + 1


Solving 2tan(x) - 3sin(x) = 0 for -pi ≤ x < pi


What is the point of a derivative?


For what values of k does the graph y=x^(2)+2kx+5 not intersect the x-axis


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences