A particle, P, moves along the x-axis. At time t seconds, t > 0, the displacement, is given by x=1/2t^2(t ^2−2t+1).

Find the times when is instantaneously at rest.In order to solve this question we first have to multiply out in order to obtain the full expression of x which will be x = 1/2t^4 -2t^3+1/2t^2. Now we differentiate with respect to time we obtain v=2t^3 -3t^2+t. If P is suppose to be at rest then v will be equal zero. So we obtain an equation 0=2t^3-3t^2+t and solving the equation t(2t-1)(t-1)=0 and we obtain three different answers t=0, t=1/2 and t=1 and all answers are possible.

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Answered by Aleksander K. Maths tutor

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