A particle, P, moves along the x-axis. At time t seconds, t > 0, the displacement, is given by x=1/2t^2(t ^2−2t+1).

Find the times when is instantaneously at rest.In order to solve this question we first have to multiply out in order to obtain the full expression of x which will be x = 1/2t^4 -2t^3+1/2t^2. Now we differentiate with respect to time we obtain v=2t^3 -3t^2+t. If P is suppose to be at rest then v will be equal zero. So we obtain an equation 0=2t^3-3t^2+t and solving the equation t(2t-1)(t-1)=0 and we obtain three different answers t=0, t=1/2 and t=1 and all answers are possible.

AK
Answered by Aleksander K. Maths tutor

19207 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Differentiate the function f(x) = sin(x)/(x^2 +1) , giving your answer in the form of a single fraction. Is x=0 a stationary point of this curve?


(i) Find the coordinates of the stationary point on the curve y = 3x^2 − 6/x − 2. [5] (ii) Determine whether the stationary point is a maximum point or a minimum point.


Find the derivative of the following function: f(x) = x(x^3 + 2x)


How do you simplify something of the form Acos(x) + Bsin(x) ?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning