Solve the following simultaneous equations: 3y=7+5x (1) 9x=-7y-4 (2)

Rearrange (2): x=(-7y-4)/9Substitute the value of x from (2) into (1): 3y=7+5*(-7y-4)/9 Simplify and rearrange for y: y+(35y/27)=(7/3) -(20/27)Resolve for y: y=43/62Substitute y into (1): (3*63)/62=7+5xRearrange for x and evaluate answer: x=-61/62

TD

Related Maths GCSE answers

All answers ▸

Simplify (3x^2 + x -2)/(x^2 - 1)


write (x+2)(x+3)(x+5) in the form ax^3+bx^2+cx+d


How do i find 30% of 70?


How to find the roots of a Quadratic Equation by Factorising?