Given the equations: x + 3y = 1 and 2x - y = -5, solve for x and y.

Here we have 2 simultaneous equations including the variables x and y. Because we have x in one equation and 2x in another we can approach this in 2 ways. The first method is to obtain 2x in both equations so that we can equate and solve for y. If we multiply the equation x + 3y = 1 by 2 we get: 2x +6y = 2. With this we can now equate the simultaneous equations to get 2 - 6y = -5 + y, where we now only have the variable y which we can calculate as being equal to 1. With this information we can now sub y = 1 into the equation x + 3y = 1, which we solve to get x = -2. Therefore, we have solved the simultaneous equations and got x = -2 and y = 1, (we can check the results by plugging the values into the initial equations to make sure they work)

JF
Answered by Jake F. Maths tutor

5101 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

25= x2 + 10 - 6. Find X


Why do you times the reciprocal of the second fraction by the first when dividing fractions.


each month Rohan spends all his income on rent, travel and other living expenses. 1/3 of his income is used for rent, 1/5 on travel and £420 on other living expenses ... work out his income each month


Solve the simultaneous equations y = 2x-3 and x^2 +y^2 = 2


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences