solve x^3+2x^2+x=0
factorise x3+2x2+x=0 => x(x2+2x+1)=0 => x(x+1)(x+1)=0 => x(x+1)2=0 => This leads to x=0 and (x+1)2=0 so x=0 and x+1=0 => Giving us the answer x=0,-1
RR
factorise x3+2x2+x=0 => x(x2+2x+1)=0 => x(x+1)(x+1)=0 => x(x+1)2=0 => This leads to x=0 and (x+1)2=0 so x=0 and x+1=0 => Giving us the answer x=0,-1
