Suppose we have a circle with the equation x^2 +y^2 =25. What is the equation to the tangent to the circle at point (4,3)?

Firstly lets draw it out-Draw a line from the origin to the point. calculate the change in y over change in x =(3-0)/(4-0)=3/4Take negative reciprocal which is equal to m. Then do y-y1=m(x-x1 ) or y = mx +c to get the final answer y=-(4/3)+25/3

NM
Answered by Nayan M. Maths tutor

3100 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve 4(x-5)=18


GCSE: How do you find the bearing of point B from A?


f(x) = x^2 + 2x - 3. Where does the graph of the function f intersect the x-axis?


All tickets for a concert are at the same price. Amy and Dan pay £63 altogether for some tickets. Amy pays £24.50 for 7 tickets. How many tickets does Dan buy?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning