Solve the simultaneous equation: 3x + 2y = 4 , 4x + 5y = 17

the first thing to do when trying to solve simultaneous equations like this one is to look for a common coefficient. one of these doesn't exist in either equation therefore you have to multiply one or both of the equations to find a common coeficient. In this case you need to multiply the first equation by 5 and the second equation by 2 to find a common coefficient between the y terms. This leaves us with 15x + 10 y = 20, 8x + 10y = 34. now you must minus the second equation from the first to eliminate the y coefficients leaving us with 7x = -14. You can then see that x = -2. We can now substitute this back into either of the starting equations. 3*-2 + 2y = 4, which simplifies to 2y = 10 which shows us that y = 5. You then have the answer to the question x = -2, y = 5.

MJ
Answered by Mohammad J. Maths tutor

2943 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Make x the subject of the following formula: 2x-4=2y.


Solve the simultaneous equations 3x+5y=7, 2x-3y=11


Write the equation x^2 + 6x - 40 = 0 in the form (x + a)^2 - b = 0 and then solve for x


How do I work out the area of a quarter circle with radius 6cm?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning